将QML信号连接到PySide2插槽

在这些情况下，最佳实践是创建一个QObject，将其导出到QML并在那里进行连接，这也是在C ++中完成的。

main.py

from PySide2.QtCore import QObject, QUrl, Slotfrom PySide2.QtGui import QGuiApplicationfrom PySide2.QtQml import QQmlApplicationEngineclass Foo(QObject):    @Slot(str)    def test_slot(self, string):        print(string)if __name__ == "__main__":    import os    import sys    app = QGuiApplication()    foo = Foo()    engine = QQmlApplicationEngine()    engine.rootContext().setContextProperty("foo", foo)    qml_file = "main.qml"    current_dir = os.path.dirname(os.path.realpath(__file__))    filename = os.path.join(current_dir, qml_file)    engine.load(QUrl.fromLocalFile(filename))    if not engine.rootObjects():        sys.exit(-1)    sys.exit(app.exec_())

main.qml

import QtQuick 2.13import QtQuick.Controls 2.13ApplicationWindow {    visible: true    Button {        anchors.centerIn: parent        text: "Example"        onClicked: foo.test_slot("Test")    }}

注意： 所有C ++ / QML良好实践也都适用于Python / QML，且更改和限制最少。