∵f'(c)=0由f'(c)-f'(0)=cf''(ξ1)可得f'(0)=-cf''(ξ1)|f'(0)|=|cf''(ξ1)|≤Mc同理|f'(a)|=|(a-c)f''(ξ2)|≤M(a-c)∴|f'(0)|+|f'(a)|≤Mc+M(a-c)=Ma
考研数学中值定理证明该怎么学
∵f'(c)=0由f'(c)-f'(0)=cf''(ξ1)可得f'(0)=-cf''(ξ1)|f'(0)|=|cf''(ξ1)|≤Mc同理|f'(a)|=|(a-c)f''(ξ2)|≤M(a-c)∴|f'(0)|+|f'(a)|≤Mc+M(a-c)=Ma
考研数学中值定理证明该怎么学名师互学网 版权所有 (c)2021-2022 ICP备案号：晋ICP备2021003244-6号
