| 分解因式:ab+b2-ac-bc=(______)-(ac+bc)=______. |
答案:
| ab+b2-ac-bc =(ab+b2)-(ac+bc) =b(a+b)-c(a+b) =(a+b)(b-c). 故答案为:ab+b2,(a+b)(b-c). |

| 分解因式:ab+b2-ac-bc=(______)-(ac+bc)=______. |
答案:
| ab+b2-ac-bc =(ab+b2)-(ac+bc) =b(a+b)-c(a+b) =(a+b)(b-c). 故答案为:ab+b2,(a+b)(b-c). |