输入一个整数金额,钞票面值有100,50,20,10,5,2,1
判断各面值所需的钞票数(要求钞票数量尽可能少)
#include#include using namespace std; int main() { int a; scanf_s("%d",&a); printf("number(100)=%dn", a/100); printf("number(50)=%dn", (a%100)/50); printf("number(20)=%dn",(a%100%50)/20); printf("number(10)=%dn", (a%100%50%20)/10); printf("number(5)=%dn", (a%100%50%20%10)/5); printf("number(2)=%dn", (a%100%50%20%10%5)/2); printf("number(1)=%dn", (a%100%50%20%10%5%2)/1); return 0; }



