【程序设计实验报告（1）口算比赛】（中二版）

 教师出题系统

//由于题目难度不同，要求生成的问题里的题目的数据以及符号的范围是不同的，（比如easy难度要求题目的数据是在1～9，符号限于加减）
//根据原始的老版本程序也就是old··question的生成数据和符号的方式，进行了优化，确保代码简便性
#include
#include
#include
typedef struct problem
{
    int a;
    char x;
    int b;
}T;
typedef struct question
{
    int e;
    char X;
    int f;
    char y;
    int g;
    char Y;
    int h;
}P;
typedef struct xxxx
{   
    char x[10];
}K;
int ANSWER(int a,char x,int b)
{
    int n=0;
    if(x=='+')
    {
        n=a+b;
    }
    else if(x=='-')
    {
        n=a-b;
    }
    else if(x=='*')
    {
        n=a*b;
    }
    else if(x=='/')
    {
        n=a/b;
    }
    return n;
}
int main()
{
   FILE *question0;
   FILE *question1;
   FILE *question2;
   FILE *open0;
   FILE *open1;
   FILE *open2;
   FILE *A0;
   FILE *A1;
   FILE *A2;
   question0 = fopen("easy.txt","w");
   question1 = fopen("medium.txt","w");
   question2 = fopen("difficult.txt","w");
   open0 = fopen("easy.txt","r");
   open1 = fopen("medium.txt","r");
   open2 = fopen("difficult.txt","r");
   A0 = fopen("answer-easy.txt","w");
   A1 = fopen("answer-medium.txt","w");
   A2 = fopen("answer-difficult.txt","w");
   srand((unsigned)time(NULL));//播种，使得rand（）函数在程序运行的每个时刻生成的随机数都是不同的
   int a,b,k,i,c,N;
   int v,j,f,l;
   int a0,a1;
   T Q[21];
   P U[21];
   K DIO[21],JO[21];
   char x;
   printf("************************************************************************n");
   printf("********************  JO小鬼居然来挑战我DIO大人了  *********************n");
   printf("************************************************************************n");
   printf("********************  木大木大木大木大木大木大木大  ********************n");
   printf("************************************************************************n");
   printf("*****************************  来吧，展示  *****************************n");
   printf("************************************************************************n");
   printf("************************  The Torld 砸哇路多  **************************n");
   printf("************************************************************************n");
   //easy
   for(i=0;i<20;i++)
   {
      a=rand()%9+1;//rand（）函数直接用了空函数，在这个文件中也没有定义【这样的目的是为了简便】，此后的time（）函数也是一样，因为这是对于文件的调用，rand（）函数和srand（）函数都在头文件stdlib.h中声明了，而函数的实现在源文件中（具体是哪个我目前还不清楚（应该是stdlib.c文件（因为头文件叫stdlib.h，源文件应该是和它重名的），而且这个应该是C自带的源文件），但是一定是C自带的源文件（某.c文件，包含rand（）和srand（）函数的定义，所有的库函数都是这样的），因此直接用空函数就行，函数直接在源文件（stdlib.c文件）中就实现了【其实原理就是“文件包含”中的对于文件的引用，不过是引用的C自带的头文件罢了】
      b=rand()%9+1;
      k=rand()%2;//根据k的返回值来判定生成的是加号还是减号
      if(a100)
      {
         i--;
         continue;
      }
      fprintf(question1,"%d",a);
      fprintf(question1,"%c",m);
      fprintf(question1,"%dn",b);
      a1=ANSWER(a,m,b);
      fprintf(A1,"%dn",a1);
   }  

//difficult
for(i=0;i<20;i++)
   {
      int q=0,c,d;
      a=rand()%9+1;
      b=rand()%9+1;
      c=rand()%9+1;
      d=rand()%9+1;
      k=rand()%4;
      if(a%b==0||c%d==0)
      {
         i--;
         continue;
      }
      if(a/b-c/d<0)
      {
         i--;
         continue;
      }
      else if(b%a==0)
      {
         b/=a;
         a=1;
         fprintf(question2,"%d",a);
         fprintf(question2,"/");
         fprintf(question2,"%d",b);
      }
      else if(a%b!=0&&b%a!=0)
      {
            for(q=2;q<10;q++)
         {
            if(a%q==0&&b%q==0)
            {
               a/=q;
               b/=q;
            }
         }
         fprintf(question2,"%d",a);
         fprintf(question2,"/");
         fprintf(question2,"%d",b); 
      } 
      switch(k)//根据k的返回值来判定生成哪种运算符
      {
         case 0:
         fprintf(question2,"+");
         x='+';
         break;
         case 1:
         fprintf(question2,"-");
         x='-';
         break;
         case 2:
         fprintf(question2,"*");
         x='*';
         break;
         case 3:
         fprintf(question2,"/");
         x='/';
         break;
      }
      if(d%c==0)
      {
         d/=c;
         c=1;
         fprintf(question2,"%d",c);
         fprintf(question2,"/");
         fprintf(question2,"%dn",d);
      }
      else if(c%d!=0&&d%c!=0)
      {
         for(q=2;q<10;q++)
         {
            if(c%q==0&&d%q==0)
            {
               c/=q;
               d/=q;
            }
         }
         fprintf(question2,"%d",c);
         fprintf(question2,"/");
         fprintf(question2,"%dn",d);
      }
      if(x=='+')
      {
         v=a*d;
         j=c*b;
         f=b*d;
         l=v+j;
         if(l%k==0)
         {
            fprintf(A2,"%dn",l/f);
         }
         else if(f%l==0)
         {
            fprintf(A2,"1");
            fprintf(A2,"/");
            fprintf(A2,"%dn",k/l);
         }
         else if(l%f!=0&&f%l!=0)
         {
            for(int NN=2;NN<10;NN++)
            {
               if(l%NN==0&&f%NN==0)
               {
                  l/=NN;
                  f/=NN;
               }
            }
            fprintf(A2,"%d",l);
            fprintf(A2,"/");
            fprintf(A2,"%dn",f);
         }
      }
      else if(x=='-')
      {
         v=a*d;
         j=c*b;
         f=b*d;
         l=v-j;
         if(l%f==0)
         {
            fprintf(A2,"%dn",l/f);
         }
         else if(f%l==0)
         {
            fprintf(A2,"1");
            fprintf(A2,"/");
            fprintf(A2,"%dn",f/l);
         }
         else if(l%f!=0&&f%l!=0)
         {
            for(int NN=2;NN<10;NN++)
            {
               if(l%NN==0&&f%NN==0)
               {
                  l/=NN;
                  f/=NN;
               } 
            }
            fprintf(A2,"%d",l);
            fprintf(A2,"/");
            fprintf(A2,"%dn",f);
         }
      }
      else if(x=='*')
      {
         l=a*b;
         f=c*d;
         if(l%f==0)
         {
            fprintf(A2,"%dn",l/f);
         }
         else if(f%l==0)
         {
            fprintf(A2,"1");
            fprintf(A2,"/");
            fprintf(A2,"%dn",f/l);
         }
         else if(l%f!=0&&f%l!=0)
         {
            for(int NN=2;NN<10;NN++)
            {
               if(l%NN==0&&f%NN==0)
               {
                  l/=NN;
                  f/=NN;
               } 
            }
            fprintf(A2,"%d",l);
            fprintf(A2,"/");
            fprintf(A2,"%dn",f);
         }
      }
      else if(x=='/')
      {
         l=a*d;
         f=b*c;
         if(l%f==0)
         {
            fprintf(A2,"%dn",l/f);
            }
         else if(f%l==0)
         {
            fprintf(A2,"1");
            fprintf(A2,"/");
            fprintf(A2,"%dn",f/l);
         }
         else if(l%f!=0&&f%l!=0)
         {
            for(int NN=2;NN<10;NN++)
            {
               if(l%NN==0&&f%NN==0)
               {
                  l/=NN;
                  f/=NN;
               } 
            }
            fprintf(A2,"%d",l);
            fprintf(A2,"/");
            fprintf(A2,"%dn",k);
         }
      }
   }
   fclose(question0);
   fclose(question1);
   fclose(question2);
   fclose(open0);
   fclose(open1);
   fclose(open2);
   fclose(A0);
   fclose(A1);
   fclose(A2);
   return 0;
} 

学生做题系统

#include
#include
typedef struct problem
{
    int a;
    char x;
    int b;
}T;
typedef struct question
{
    int e;
    char X;
    int f;
    char y;
    int g;
    char Y;
    int h;
}P;
typedef struct xxxx
{   
    char x[10];
}K;
int ANSWER(int a,char x,int b)
{
    int n=0;
    if(x=='+')
    {
        n=a+b;
    }
    else if(x=='-')
    {
        n=a-b;
    }
    else if(x=='*')
    {
        n=a*b;
    }
    else if(x=='/')
    {
        n=a/b;
    }
    return n;
}
int main()
{
    FILE *open0;
    FILE *open1;
    FILE *open2;
    FILE *A0;
    FILE *A1;
    FILE *A2;
    open0 = fopen("easy.txt","r");
    open1 = fopen("medium.txt","r");
    open2 = fopen("difficult.txt","r");
    A0 = fopen("answer-easy.txt","r");
    A1 = fopen("answer-medium.txt","r");
    A2 = fopen("answer-difficult.txt","r");
    T Q[21];
    P U[21];
    K DIODIO[21],JOJO[21];
    printf("************************************************************************n");
    printf("***** 欢迎你，乔斯达血脉的人啊，看来你已经展示了你背后的星星印记了 *****n");
    printf("************************************************************************n");
    printf("***********************  那么前来挑战我DIO吧  **************************n");
    printf("************************************************************************n");
    printf("***********************  选择你的难度吧JOJO  ***************************n");
    printf("************************************************************************n");
    printf("************************  选择“简单”输入“0”  ***************************n");
    printf("************************************************************************n");
    printf("************************  选择“中等”输入“1”  ***************************n");
    printf("************************************************************************n");
    printf("************************  选择“困难”输入“2”  ***************************n");
    printf("************************************************************************n");
    int difficulty;
    int JO[21]={0},DIO[21]={10};
    int N,MISSDA=0;
    char W[10];
    scanf("%d",&difficulty);
    printf("************************  赛高泥high铁鸭子哒  **************************n");
    printf("***************************  让我们开始吧  *****************************n");
    time_t start,end;
    start=time(NULL);
    if(difficulty==0)
    {
        for(N=0;N<20;N++)
        {
            fscanf(open0,"%d",&Q[N].a);
            fscanf(open0,"%c",&Q[N].x);
            fscanf(open0,"%d",&Q[N].b);
            printf("%d",Q[N].a);
            printf("%c",Q[N].x);
            printf("%dn",Q[N].b);
            printf("回答吧，食堂泼辣酱n");
            scanf("%d",&DIO[N]);
        }
    }
    else if (difficulty==1)
    {
        for(N=0;N<20;N++)
        {
            fscanf(open1,"%d",&Q[N].a);
            fscanf(open1,"%c",&Q[N].x);
            fscanf(open1,"%d",&Q[N].b);
            printf("%d",Q[N].a);
            printf("%c",Q[N].x);
            printf("%dn",Q[N].b);
            printf("回答吧，食堂泼辣酱n");
            scanf("%d",&DIO[N]);
        }
    }
    else if (difficulty==2)
    {
        for(N=0;N<20;N++)
        {
            fscanf(open2,"%d",&U[N].e);
            fscanf(open2,"%c",&U[N].X);
            fscanf(open2,"%d",&U[N].f);
            fscanf(open2,"%c",&U[N].y);
            fscanf(open2,"%d",&U[N].g);
            fscanf(open2,"%c",&U[N].Y);
            fscanf(open2,"%d",&U[N].h);
            printf("%d",U[N].e);
            printf("%c",U[N].X);
            printf("%d",U[N].f);
            printf("%c",U[N].y);
            printf("%d",U[N].g);
            printf("%c",U[N].Y);
            printf("%dn",U[N].h);
            printf("回答吧，食堂泼辣酱n");
            scanf("%s",DIODIO[N].x);
        }
    }
    end=time(NULL);
    FILE *fp = NULL;
    time_t timep;
    struct tm *p;
    char name[256] = {0},g[10]={0};
    time(&timep);//获取从1970至今过了多少秒，存入time_t类型的timep
    p = localtime(&timep);//用localtime将秒数转化为struct tm结构体
    sprintf(name, "%d.%d.%d %d:%02d.txt",1900+p->tm_year,1+p->tm_mon,p->tm_mday,p->tm_hour,p->tm_min);//把格式化的时间写入字符数组中
    if((fp = fopen(name, "w")) == NULL)
        perror("");
    for(N=0;N<20;N++)
    {
        if(difficulty==0)
        {
            fprintf(fp,"%dn",DIO[N]);
            fscanf(A0,"%d",&JO[N]);
            if(JO[N]==DIO[N])
            {
                MISSDA+=5;
            }
        }
        if(difficulty==1)
        {
            fprintf(fp,"%dn",DIO[N]);
            fscanf(A1,"%d",&JO[N]);
            if(JO[N]==DIO[N])
            {
                MISSDA+=5;
            }
        }
        if(difficulty==2)
        {
            fprintf(fp,"%sn",DIODIO[N].x);
            fscanf(A2,"%s",JOJO[N].x);
            if(JOJO[N].x==DIODIO[N].x)
            {
                MISSDA+=5;
            }
        }
    }
    int H=difftime(end,start);
    fprintf(fp,"******* 在你解答的时间里，我的砸瓦鲁多时间过了 %d 秒 *******n",H);
    fprintf(fp,"************** 你的绿宝石水花居然得了 %d 分 **************n",MISSDA);
    fprintf(fp,"********************** 咱就是说 **********************n");
    fprintf(fp,"************************ 虽然 ***********************n");
    fprintf(fp,"************** 我不记得我吃了多少片小面包 **************n");
    fprintf(fp,"************** 但是老东西你的替身最没用啦 **************n");
    fprintf(fp,"***************** 赛高泥high铁鸭子哒 *****************n");
    fclose(open0);
    fclose(open1);
    fclose(open2);
    fclose(A0);
    fclose(A1);
    fclose(A2);
    return 0;
}