在调用python的某些类时，事先并不确定参数的，需要自行拼接字符串。解决办法如下，
参考：
https://stackoverflow.com/questions/48838289/pass-string-parameter-into-class-function-pythonhttps://stackoverflow.com/questions/48838289/pass-string-parameter-into-class-function-python
给出我的代码示例：
# 生成kwargs字符串，比如 host="1", port="2", user="3", password="4", database="5", schema="6", table="7", fileName="8"
kwagrsStr = """host="1", port="2", user="3", password="4", database="5", schema="6", table="7", fileName="8" """
class dataConnector():
def __init__(self, **kwargs):
# 主机
self.host = 'host' in kwargs and kwargs['host'] or None
# 端口
self.port = 'port' in kwargs and kwargs['port'] or None
# 用户名
self.user = 'user' in kwargs and kwargs['user'] or None
# 密码
self.password = 'password' in kwargs and kwargs['password'] or None
# 数据库
self.database = 'database' in kwargs and kwargs['database'] or None
# schema
self.schema = 'schema' in kwargs and kwargs['schema'] or None
# table
self.table = 'table' in kwargs and kwargs['table'] or None
# fileName
self.fileName = 'fileName' in kwargs and kwargs['fileName'] or None
def run(self):
print(self.host, self.port, self.user, self.password, self.database, self.schema, self.table, self.fileName)
# 引用某个类
dbObject = dataConnector(**eval("dict({})".format(kwagrsStr)))
dbObject.run()
