如何在python中解析多种（未知）日期格式？

import ress = '''10/02/0907/22/0909-08-20089/9/200811/4/201003-07-200909/01/2010'''regx = re.compile('[-/]')for xd in ss.splitlines():    m,d,y = regx.split(xd)    print xd,'   ','/'.join((m.zfill(2),d.zfill(2),'20'+y.zfill(2) if len(y)==2 else y))

结果

10/02/09     10/02/200907/22/09     07/22/200909-08-2008     09/08/20089/9/2008     09/09/200811/4/2010     11/04/201003-07-2009     03/07/200909/01/2010     09/01/2010

编辑1

而 编辑2 ：考虑到的信息

'{0:0>2}'.format(day)

import refrom time import clockiterat = 100from datetime import datetimedates = ['10/02/09', '07/22/09', '09-08-2008', '9/9/2008', '11/4/2010',         ' 03-07-2009', '09/01/2010']reobj = re.compile(r"""s*  # optional whitespace(d+)    # Month[-/]     # separator(d+)    # Day[-/]     # separator(?:20)?  # century (optional)(d+)    # years (YY)s*      # optional whitespace""",re.VERBOSE)te = clock()for i in xrange(iterat):    ndates = (reobj.sub(r"1/2/203", date) for date in dates)    fdates1 = [datetime.strftime(datetime.strptime(date,"%m/%d/%Y"), "%m/%d/%Y")    for date in ndates]print "Tim's method   ",clock()-te,'seconds'regx = re.compile('[-/]')te = clock()for i in xrange(iterat):    ndates = (reobj.match(date).groups() for date in dates)    fdates2 = ['%s/%s/20%s' % tuple(x.zfill(2) for x in tu) for tu in ndates]print "mixing solution",clock()-te,'seconds'te = clock()for i in xrange(iterat):    ndates = (regx.split(date.strip()) for date in dates)    fdates3 = ['/'.join((m.zfill(2),d.zfill(2),('20'+y.zfill(2) if len(y)==2 else y)))   for m,d,y in ndates]print "eyquem's method",clock()-te,'seconds'te = clock()for i in xrange(iterat):    fdates4 = ['{:0>2}/{:0>2}/20{}'.format(*reobj.match(date).groups()) for date in dates]print "Tim + format   ",clock()-te,'seconds'print fdates1==fdates2==fdates3==fdates4

结果

number of iteration's turns : 100Tim's method    0.295053700959 secondsmixing solution 0.0459111423379 secondseyquem's method 0.0192239516475 secondsTim + format    0.0153756971906 seconds True

混合解决方案很有趣，因为它结合了我的解决方案的速度和Tim Pietzcker的正则表达式 检测 字符串中日期的能力。

对于将Tim的格式与结合使用的解决方案而言，情况更是如此

{:0>2}

{:0>2}

regx.split(date.strip())