如何使用python将文本文件拆分为多个文本文件？

尝试re.findall（）函数：

import rewith open('input.txt', 'r') as f:    data = f.read()found = re.findall(r'n*(A.*?n$$)n*', data, re.M | re.S)[open(str(i)+'.txt', 'w').write(found[i-1]) for i in range(1, len(found)+1)]

前3次出现的 简约方法：

import refound = re.findall(r'n*(A.*?n$$)n*', open('input.txt', 'r').read(), re.M | re.S)[open(str(found.index(f)+1)+'.txt', 'w').write(f) for f in found[:3]]

一些解释：

found = re.findall(r'n*(A.*?n$$)n*', data, re.M | re.S)

将查找与指定RegEx匹配的所有匹配项，并将它们放入 列表中 ，称为

found

[open(str(found.index(f)+1)+'.txt', 'w').write(f) for f in found]

遍历（属于列表）所有元素（使用列表推导），

found

index of the element +1

没有RegEx的另一个版本：

blocks_to_read = 3blk_begin = 'A'blk_end = '$$'with open('35916503.txt', 'r') as f:    fn = 1    data = []    write_block = False    for line in f:        if fn > blocks_to_read: break         line = line.strip()        if line == blk_begin: write_block = True        if write_block: data.append(line)        if line == blk_end: write_block = False with open(str(fn) + '.txt', 'w') as fout:     fout.write('n'.join(data))     data = [] fn += 1

PS我个人不喜欢这个版本，我会使用RegEx