在int []数组中找到最受欢迎的元素

public int getPopularElement(int[] a){  int count = 1, tempCount;  int popular = a[0];  int temp = 0;  for (int i = 0; i < (a.length - 1); i++)  {    temp = a[i];    tempCount = 0;    for (int j = 1; j < a.length; j++)    {      if (temp == a[j])        tempCount++;    }    if (tempCount > count)    {      popular = temp;      count = tempCount;    }  }  return popular;}