[C++]模板类的继承

1.  模块基类不用指定传参类型

// 定义模板类，作为父类
template  class People
{
public:
	T x;
	People(){};
	People(T a):x(a){};
};

// 定义派生类
template  class Man:public People
{
public:
	T y;
	Man(){};
	Man(T a):y(a){};
	Man(T a, T b):People(a),y(b){};

};

// 类的使用
int main(void)
{
	Man m1(3, 7);			// a=3 b=7  a对应x，b对应y，所以x=3，y=7
	cout << "x = " << m1.x << ", y = " << m1.y << endl;
	return 0;
}

2. 模板基类也可以指定传参类型

// 定义模板类，作为父类
template  class People
{
public:
	T x;
	People(){};
	People(T a):x(a){};
};

// 定义派生类，继承模板类，指定派生类传入 double 类型
template  class Man:public People
{
public:
	T y;
	Man(){};
	Man(T a):y(a){};
	Man(double a, T b):People(a),y(b){};
};

3. 普通类继承模板类

// 定义模板类，作为父类
template  class People
{
public:
	T x;
	People(){};
	People(T a):x(a){};
};

//普通类继承模板类
class Man:public People
{
public:
	double y;
	Man(){};
	Man(double a):y(a){};
	Man(double a, double b):People(a),y(b){};		// x在前，y在后
};

4. 类模板继承普通类

// 定义基类，普通类
class People
{
public:
	double x;
	People(){};
	People(double a):x(a){};
};

// 派生类，类模板继承普通类
template  class Man:public People
{
public:
	T y;
	Man(){};
	Man(T a):y(a){};
	Man(double a, T b):People(a),y(b){};
};