MySQL内核解析之二进制结果集协议分析 Binary ResultSet

来源：

https://dev.mysql.com/doc/internals/en/binary-protocol-resultset.html

01 00 00 01 01|1a 00 00    02 03 64 65 66 00 00 00    ..........def...
04 63 6f 6c 31 00 0c 08    00 06 00 00 00 fd 00 00    .col1...........
1f 00 00|05 00 00 03 fe    00 00 02 00|09 00 00 04    ................
00 00 06 66 6f 6f 62 61    72|05 00 00 05 fe 00 00    ...foobar.......
02 00 

拆分分析：

1、01 00 00 01 01   
2、1a 00 00 02 03 64 65 66 00 00 00 04 63 6f 6c 31 00 0c 08 00 06 00 00 00 fd 00 00 1f 00 00    def :64 65 66
3、05 00 00 03 fe 00 00 02 00  EOF_Packet
============================================
4、09 00 00 04 00 00 06 66 6f 6f 62 61 72            {Binary Protocol Resultset Row}        foobar:66 6f 6f 62 61 72     URL
5、05 00 00 05 fe 00 00 02 00  EOF_Packet

============================================

从两次发送EOF分析：

第一轮：发送字段信息（元数据）;

第二轮：发送相关数据（values）；

01 00 00 01 01       column_count =  01，列的个数为1

以此类推：

01 00 00 01 0c       column_count =  0c，列的个数为12

参考：https://dev.mysql.com/doc/internals/en/packet-EOF_Packet.html

00 00                number of warnings
02 00                status flag  0x0002 = **SERVER_STATUS_AUTOCOMMIT**
（A MySQL 4.1 EOF packet with: 0 warnings, AUTOCOMMIT enabled.）

ASCII对照表

Protocol::ColumnDefinition41

03                                 变长字段：  lenenc_str = 3，def
64 65 66                       def  catalog (always "def")
00                                 schema
00                                 table
00                                 org_table
04                                 变长字段：  lenenc_str = 4 ，col1
63 6f 6c 31                   col1，virtual column name
00                                 physical column name
0c                                 length of the following fields (always 0x0c)  = 以下是12个固定字段：长度不变，字节内容可变
08 00                            latin1_swedish_ci  (0x08)
06 00 00 00                   maximum length of the field
fd                                  Protocol::MYSQL_TYPE_VAR_STRING  (0xfd)
00 00                            flags
1f                                  for dynamic strings, double, float
00 00                            filler [00] [00]

参考：https://blog.csdn.net/zhangh571354026/article/details/120437902?spm=1001.2014.3001.5501

00                                        这里没有NULL所以：（1+7+2）/ 8 = 1,(占用1个空间），（无表示，全0）
06                                        变长字段，lenenc_str = 6  
66 6f 6f 62 61 72                values=foobar