java查找图中两点之间所有路径

本文实例为大家分享了java查找图中两点之间所有路径的具体代码，基于邻接表，供大家参考，具体内容如下

图类：

package graph1;
 
import java.util.linkedList;
 
import graph.Graph.edgeNode;
 
public class Graph {
 
 class EdgeNode{
  int adjvex;
  EdgeNode nextEdge;
 }
 
 class VexNode{
 int data;
 EdgeNode firstEdge;
 boolean isVisted;
 public boolean isVisted() {
  return isVisted;
 }
 public void setVisted(boolean isVisted) {
  this.isVisted = isVisted;
 }
 
 }
 
 VexNode[] vexsarray ;
 int[] visited = new int[100];
 boolean[] isVisited = new boolean[100];
 
 public void linkLast(EdgeNode target,EdgeNode node) {
 while (target.nextEdge!=null) {
  target=target.nextEdge;
 }
 target.nextEdge=node;
 }
 
 public int getPosition(int data) {
  for(int i=0;i

算法：

package graph1;
 
import java.util.HashMap;
import java.util.Map;
import java.util.Stack;
 
import javax.swing.plaf.synth.SynthStyle;
 
import graph1.Graph.EdgeNode;
 
public class FindALlPath {
 
 
 //代表某节点是否在stack中,避免产生回路 
 public Map states=new HashMap(); 
  
 //存放放入stack中的节点 
 public Stack stack=new Stack(); 
 
 //打印stack中信息,即路径信息 
 public void printPath(){ 
   StringBuilder sb=new StringBuilder(); 
   for(Integer i :stack){ 
     sb.append(i+"->"); 
   } 
   sb.delete(sb.length()-2,sb.length()); 
   System.out.println(sb.toString()); 
 } 
 
 //得到x的邻接点为y的后一个邻接点位置,为-1说明没有找到 
 public int getNextNode(Graph graph,int x,int y){ 
   int next_node=-1; 
   EdgeNode edge=graph.vexsarray[x].firstEdge; 
   if(null!=edge&&y==-1){ 
     int n=edge.adjvex; 
     //元素还不在stack中 
     if(!states.get(n)) 
return n; 
     return -1; 
   } 
      
   while(null!=edge){ 
     //节点未访问 
     if(edge.adjvex==y){ 
if(null!=edge.nextEdge){ 
next_node=edge.nextEdge.adjvex; 

if(!states.get(next_node)) 
  return next_node; 
} 
else 
  return -1; 
     } 
     edge=edge.nextEdge; 
   } 
   return -1; 
 }
 
 
 
 public void visit(Graph graph,int x,int y){ 
    //初始化所有节点在stack中的情况 
     for(int i=0;i

测试类：

package graph1;
 
import java.util.Iterator;
 
import graph1.Graph.VexNode;
 
public class Tset2 {
 
 public static void main(String[] args) {
 
 int[] vexs = {0,1,2,3,4};
 int[][] edges = {
  {0,1},
  {0,3},
  {1,0},
  {1,2},
  {2,1},
  {2,3},
  {2,4},
  {3,0},
  {3,2},
  {3,4},
  {4,2},
  {4,3},
  
 };
 Graph graph = new Graph();
 graph.buildGraph(vexs, edges);
 graph.printGraph();
 
 
 FindALlPath findALlPath = new FindALlPath();
 findALlPath.visit(graph, 4, 0);
 
 }
 
}



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