计算:1/a-1+1/(a-1)(a-2)+1/(a-2)(a-3)+……+1/(a-2010)(a-2011)谢谢了,

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计算:1/a-1+1/(a-1)(a-2)+1/(a-2)(a-3)+……+1/(a-2010)(a-2011)谢谢了,

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2026-06-04 18:13:42

1/a-1+1/(a-1)(a-2)+1/(a-2)(a-3)+……+1/(a-2010)(a-2011) =1/(a-1)+1/(a-2)-1/(a-1)+1/(a-3)-1/(a-2)+。。。+1/(a-2011)-1/(a-2010) =1/(a-2011)

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  • 寒冷的店员
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    2026-06-04 18:13:42

    1/a-1+1/(a-1)(a-2)+1/(a-2)(a-3)+……+1/(a-2010)(a-2011) =1/(a-1)+1/(a-2)-1/(a-1)+1/(a-3)-1/(a-2)+。。。+1/(a-2011)-1/(a-2010) =1/(a-2011)

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