已知集合A={x︱x2+px+q=x},集合B={ x︱(x-1)2+p(x-1)+q=x+3},当A=｛2｝时,求集合

x2+px+q=xx²+(p-1)x+q=0它有两相等实根2∴2＋2=1-p2×2=q∴p=-3 q=4(x-1)²-3(x-1)+4=x+3即(x-1)²-4(x-1)=0(x-1)(x-5)=0∴x=1或x=5∴B={1,5}