化简 x²-1分之x+3÷﹣x²+2x-1分之(x+3)(x-1)

学习 时间:2026-04-04 19:18:27 阅读:5374
化简 x²-1分之x+3÷﹣x²+2x-1分之(x+3)(x-1)

最佳回答

拼搏的项链

精明的百褶裙

2026-04-04 19:18:27

(x+3)/( x²-1)÷[(x+3)(x-1)/(﹣x²+2x-1)]=(x+3)/( x²-1)÷[-(x+3)(x-1)/(x²-2x+1)]=(x+3)/( x²-1)÷[-(x+3)(x-1)/(x-1)²]=(x+3)/( x²-1)÷[-(x+3)/(x-1)]=-(x+3)/( x²-1)*(x-1)/(x+3)=-(x+3)/[( x-1)(x+1)]*(x-1)/(x+3)=-1/(x+1)

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  • 眼睛大的睫毛
    回复
    2026-04-04 19:18:27

    (x+3)/( x²-1)÷[(x+3)(x-1)/(﹣x²+2x-1)]=(x+3)/( x²-1)÷[-(x+3)(x-1)/(x²-2x+1)]=(x+3)/( x²-1)÷[-(x+3)(x-1)/(x-1)²]=(x+3)/( x²-1)÷[-(x+3)/(x-1)]=-(x+3)/( x²-1)*(x-1)/(x+3)=-(x+3)/[( x-1)(x+1)]*(x-1)/(x+3)=-1/(x+1)

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