|a+b+2|与（2ab-1)^2互为相反数,求代数式（a+b)^2/3ab-3ab/a+b+1的值. 速度啊 速度啊.

∵|a+b+2|与（2ab-1)²互为相反数∴|a+b+2|+(2ab-1)²=0∴a+b+2=0,2ab-1=0∴a+b=-2,ab=1/2∴(a+b)²=4,3ab=3/2,a+b+1=-1∴（a+b)²/3ab-3ab/(a+b+1) =4/(3/2)-(3/2)/(-1) =8/3+3/2 =16/6+9/6 =25/6 =4又1/6