- 1.包含字典的嵌套字典,转DataFrame
- 2. 利用包含等长度列表或NumPy数组的 字典dict 来形成DataFrame
import pandas as pd
pop = {'Nevada': {2001: 2.4, 2002: 2.9},
'Ohio': {2000: 1.5, 2001: 1.7, 2002: 3.6}}
frame = pd.DataFrame(pop)
frame
Out[3]:
Nevada Ohio
2001 2.4 1.7
2002 2.9 3.6
2000 NaN 1.5
类似于numpy的转置:
frame.T
Out[4]:
2001 2002 2000
Nevada 2.4 2.9 NaN
Ohio 1.7 3.6 1.5
2. 利用包含等长度列表或NumPy数组的 字典dict 来形成DataFrame
注意:等长度 的列表或数组
data = {'state': ['Ohio', 'Ohio', 'Ohio', 'Nevada', 'Nevada', 'Nevada'],
'year': [2000, 2001, 2002, 2001, 2002, 2003],
'pop': [1.5, 1.7, 3.6, 2.4, 2.9, 3.2]}
frame = pd.DataFrame(data)
frame
Out[8]:
state year pop
0 Ohio 2000 1.5
1 Ohio 2001 1.7
2 Ohio 2002 3.6
3 Nevada 2001 2.4
4 Nevada 2002 2.9
5 Nevada 2003 3.2
指定列的顺序
pd.DataFrame(data, columns=['year', 'state', 'pop']) Out[9]: year state pop 0 2000 Ohio 1.5 1 2001 Ohio 1.7 2 2002 Ohio 3.6 3 2001 Nevada 2.4 4 2002 Nevada 2.9 5 2003 Nevada 3.2



