欧拉计划Problem

思路：暴力解

C#

#include
#include
int main(){
    int a=1,b=1,c=1;
    long mul = 0;
    for (a = 1; a < 1000; a++){
        for(b = a;b <= (1000-a) ;b++){
            for(c = b;c <= (1000-a-b);c++){
                if((a*a+b*b== c*c) && (a+b+c==1000))
                    //printf("%d %d %dn",a,b,c);
                    mul = a*b*c;
            }
        }
    }
    printf("%d",mul);
    return 0;
}

JAVA

package exercise;

public class _特殊毕达哥拉斯三元组 {

	public static void main(String[] args) {
		for(int a=1;a<1000;a++) {
			for(int b=1;b<1000;b++) {
				for(int c=1;c<1000;c++){
					if((a 
结果：31875000