confusion = {}
confusion[1] = 1
confusion['1'] = 2
confusion[1] += 1
sum = 0
for k in confusion:
sum += confusion[k]
print(sum)
问题描述
此时confusion={1:2,'1':1}
k=1,confusion[1]=2
sum的值？
斐波纳契数列。：
#!/usr/bin/python3
# Fibonacci series: 斐波纳契数列
# 两个元素的总和确定了下一个数
a, b = 0, 1
while b < 10:
print(b)
a, b = b, a+b
