Java对String对象内容进行排序

方法一：

String strToSorted = new String("cdeafghibaefh");
char[] charArray = strToSorted.toCharArray();
Arrays.sort(charArray);
System.out.println(charArray);

方法二：

        String strToSorted = "strToSorted";
        List charList = asList(strToSorted.toCharArray());
        Collections.sort(charList);
        char[] chars = new char[charList.size()];
        for (int i = 0; i < charList.size(); i++) {
            chars[i] = charList.get(i);
        }
        System.out.println(chars);

方法三（计数法）：

        String strToSorted = "strToSorted";
        char[] asciis = new char[256];
        for (int i = 0; i < strToSorted.length(); i++) {
            asciis[strToSorted.charAt(i)]++;
        }        
        char[] chars=new char[strToSorted.length()];
        int index=0;
        for (int i = 0; i < 256; i++) {
            if(asciis[i] !=0){
                int count=asciis[i];
                for (int j = 0; j < count; j++) {
                    chars[index++]= (char)i;
                }
            }
        }
        System.out.println(chars);