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如何把Map转化为query string呢?
什么是query string?
即型如name=whuang&age=27
private String getRequestBodyFromMap(Map parametersMap,boolean isUrlEncoding) {
StringBuffer sbuffer = new StringBuffer();
for(Object obj:parametersMap.keySet()){
String value=(String) parametersMap.get(obj);
if(isUrlEncoding){
try {
value = URLEncoder.encode(value, SystemHWUtil.CHARSET_UTF);
if(!ValueWidget.isNullOrEmpty(value)){
parametersMap.put(obj, value);
}
} catch (UnsupportedEncodingException e1) {
e1.printStackTrace();
}
}
sbuffer.append(obj).append("=").append(value).append("&");
}
return sbuffer.toString().replaceAll("&$", SystemHWUtil.EMPTY);
}
private StringBuffer getRequestBodyFromList(List parameters,boolean isUrlEncoding) {
StringBuffer sbuffer = new StringBuffer();
int size = parameters.size();
for (int i = 0; i < size; i++) {
ParameterIncludeBean parameterIncludeBean = parameters.get(i);
if(parameterIncludeBean.isIgnore()){
parameters.remove(parameterIncludeBean);
size--;
i--;
continue;
}
sbuffer.append(parameterIncludeBean.getQueryString(isUrlEncoding,urlEncodeParameterCharset));
if (i < size - 1) {
sbuffer.append("&");
}
}
return sbuffer;
}
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表格执行完
parameterTable_1.setModel(model); 之后一定要render,即
public void rendTable(){
parameterTable_1.getColumnModel().getColumn(2)
.setCellEditor(new MyButtonEditor());
parameterTable_1.getColumnModel().getColumn(2)
.setCellRenderer(new MyButtonRender());
if(AutoTestPanel.isTF_table_cell){//若表格的单元格是JTextField
parameterTable_1.getColumnModel().getColumn(0)
.setCellEditor(new MyTextFieldEditor());
parameterTable_1.getColumnModel().getColumn(0)
.setCellRenderer(new MyTextFieldRender());
parameterTable_1.getColumnModel().getColumn(1)
.setCellEditor(new MyTextFieldEditor());
parameterTable_1.getColumnModel().getColumn(1)
.setCellRenderer(new MyTextFieldRender());
}
final MouseInputListener mouseInputListener = getMouseInputListener(parameterTable_1,RequestPanel.this,null);
parameterTable_1.addMouseListener(mouseInputListener);
}
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原文：http://hw1287789687.iteye.com/blog/2253921
