leetcode 714. 买卖股票的最佳时机含手续费(java)

 贪心！！！

class Solution {
    public int maxProfit(int[] prices, int fee) {
        int n = prices.length;
        int buy = prices[0] + fee;
        int profit = 0;
        for (int i = 1; i < n; ++i) {
            if (prices[i] + fee < buy) {
                buy = prices[i] + fee;
            } else if (prices[i] > buy) {
                profit += prices[i] - buy;
                buy = prices[i];
            }
        }
        return profit;
    }
}