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PYTHON 深度优先算法解决迷宫问题

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PYTHON 深度优先算法解决迷宫问题

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祝各位别挂科



















#黑白迷宫转换矩形(0,1)
from PIL import Image
srcImage = Image.open("test2.jpg")
grayImage = srcImage.convert('L')
binarizedImage = grayImage.point(lambda x: 0 if x<128 else 255, '1')

from PIL import Image
from scipy.ndimage import zoom
import numpy as np


srcImage = Image.open("test.jpg")
array = np.array(grayImage)
array = zoom(array, 40/40)
np.savetxt("binarized2.txt", array<128, fmt="%d",delimiter="")

#深度优先算法
import os

from collections import *

mp = []
for i in range(40):
    mp.append(list(map(int, input())))
k = ('D', 'L', 'R', 'U')
dir = [(1, 0), (0, -1), (0, 1), (-1, 0)]  # 标记方向
vis = [[0] * 50 for i in range(40)]  # 标记走没走过
pre = [[''] * 50 for i in range(40)]  # 记录怎么来到这个点的


def print_pass(x, y):
    if x == 0 and y == 0:
        return
    if pre[x][y] == 'D':  print_pass(x - 1, y)
    if pre[x][y] == 'L':  print_pass(x, y + 1)
    if pre[x][y] == 'R':  print_pass(x, y - 1)
    if pre[x][y] == 'U':  print_pass(x + 1, y)
    print(pre[x][y], end="")


def bfs():
    global pre
    global vis
    q = deque()
    q.append((0, 0))
    vis[0][0] = 1
    while q:
        now = q.popleft()  # 删除q最左边的元素
        if now[0] == 30 and now[1] == 39:
            print_pass(30, 39)
            return
        for i in range(4):
            next = [0, 0]
            next[0] = now[0] + dir[i][0]
            next[1] = now[1] + dir[i][1]
            if next[0] < 0 or next[0] >= 40 or next[1] < 0 or next[1] >= 40:
                continue
            if vis[next[0]][next[1]] == 1 or mp[next[0]][next[1]] == 1:
                continue
            vis[next[0]][next[1]] = 1
            q.append((next[0], next[1]))
            pre[next[0]][next[1]] = k[i]


bfs()
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