#includeusing namespace std; using gg = long long; int main() { ios::sync_with_stdio(false); cin.tie(0); string input = ""; cin >> input; gg n1 = (input.size() + 2) / 3; gg n2 = input.size() + 2 - 2 * n1; //前n1-1行,需要输出首尾两个字符,且每行字符数为n2 for (int i = 0; i < n1 - 1; ++i) { cout << input[i]; for (int j = 0; j < n2 - 2; ++j) cout << " "; cout << input[input.size() - i - 1] << "n"; } //最后一行将没有输出的n2个字符一次性输出 cout << input.substr(n1 - 1, n2); return 0; }



