C语言算法：统计n的阶乘尾部零的个数（基础）

#include 
#include 
int main()
{
	int j,k,m,n,a[40000];
	long g,t;
	double s = 0;
	printf("请输入正整数n(n<10000):");
	scanf("%d",&n);
	for(k = 2 ; k <= n ; k++){
		s += log10(k);
	}
	m = (int)s+1;
	for(k = 1 ; k <= m ; k++){
		a[k] = 0;
	}
	a[1] = 1;
	g = 0;
	for(k = 2 ; k <= n ; k++){
		for(j = 1 ; j <= m; j++){
			t = a[j]*k+g;
			a[j] = t%10;
			g = t/10;
		}
	}
	j = 1;
	while(a[j] == 0){
		j++;
	}
	printf(" %d! 尾部连续零的个数为%d",n,j-1);
	return 0;
}