C++实验4 运算符重载

6-1
本题考虑对运算符进行重载。分别重载复数运算的+，-，*，/，=（赋值）运算符，以及比较大小的<=（复数1的模是否小于等于复数2的模）运算符，其中，比较运算符按复数的模进行比较。测试程序根据输入的mode值分别测试各个函数是否编写正确。
函数接口定义：

i#include 
using namespace std;

class Complex {
    double real;
    double imag;
public:
    //构造函数
    Complex(double real=0, double imag=0);

    //operator+-*/=操作符函数
    Complex operator+(const Complex& c) const;
    Complex operator-(const Complex& c) const;
    Complex operator*(const Complex& c) const;
    Complex operator/(const Complex& c) const;
    Complex operator=(const Complex& c);

    //operator <=操作符函数
    bool operator<=(const Complex& c) const;

    //友元函数声明以帮助operator<<()函数访问Complex类的私有成员
    friend ostream& operator<<(ostream& out, const Complex& c);
};

//n个复数，按模从小到达排序
void bubble_sort(Complex[],int n);

测试样例：

在这里给出函数被调用进行测试的例子：
int main() {
    double dReal1, dImag1, dReal2, dImag2;

    int mode;
    cin>>mode;
    cin>>dReal1>>dImag1>>dReal2>>dImag2;
    Complex c1(dReal1, dImag1);
    Complex c2(dReal2, dImag2);
    Complex c[6] = {c1,c2,c1+c2,c1-c2,c1*c2,c1/c2};
    switch(mode)
    {
        case 1: cout << c[0]<<" "< 
Complex::Complex(double real, double imag) {
    this->real = real;
    this->imag = imag;
}
Complex Complex::operator + (const Complex& c) const {
    return Complex(real + c.real, imag + c.imag);
}
Complex Complex::operator-(const Complex& c) const {
    return Complex(real - c.real, imag - c.imag);
}
Complex Complex::operator*(const Complex& c) const {
    return Complex(real*c.real-imag*c.imag,imag*c.real+real*c.imag);

}
Complex Complex::operator/(const Complex& c) const {
    return Complex((real * c.real + imag * c.imag) / (c.real * c.real + c.imag * c.imag), (imag * c.real - real * c.imag) / (c.real * c.real + c.imag * c.imag));

}
Complex Complex::operator=(const Complex& c) {
    return Complex(real=c.real,imag=c.imag);
}
bool Complex::operator<=(const Complex& c) const {
    if ((real * real + imag * imag) <= (c.real *c. real + c.imag * c.imag)) {
        return true;
    }
    else {
        return false;
    }
}
ostream& operator<<(ostream& out, const Complex& c) {
    if (c.imag >= 0) {
        return out << c.real<<"+" << c.imag << "i";
    }
    else {
        return out << c.real<< c.imag << "i";
    }
}
void bubble_sort(Complex fs[], int n) {
    Complex temp;
    for (int i = 0; i < n-1; i++) {
        for (int j = 0; j < n-i; j++) {
            if (fs[j+1] <= fs[j]) 
            {
                 temp = fs[j+1];
                fs[j + 1] = fs[j];
                fs[j] = temp;
                

            }
                
        }

    }

}

 
①本题在重载<=运算符时需思考：究竟<=符号左边应是传入的值还是符号右边，也就是需要弄清楚谁应该是小值，谁应该是大值。显然由程序能看出符号右边为传入的值。
 ②重载运算符＝时，自己偷懒随便写了参数，发现编译时使用mode=6s输出，始终得不到想要的结果，后重新修改正确重载=后，输出正常。
 ③冒泡排序算法n-1次外循环，内循环5!次。