广联达5.18笔试编程题LED灯

广联达5.18笔试编程题，计算每次LED灯变化时，灯管点亮或者熄灭的次数之和，输入为一个数字字符串例如：102，代表LED灯从熄灭状态变化为1，由1变化为0，由0变化为2，计算灯管熄灭或点亮的总次数。

以102为例，LED灯从熄灭状态变化为2，灯管变化次数为2，从1到0变化次数为4，从0到2变化次数为3，所以总次数为9。 

LED灯管编号：1~7（中间灯管为7）                

 熄灭到102的变化过程如下：

 C++代码：

#include 
#include 
#include
using namespace std;

int main() {
	string s;
	cin>>s;
	vector > a;
	vector b;
	int count=0;
	//a[0][0]-a[0][6]  0
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(0);
	a.push_back(b);
	b.clear();

	//a[1][0]-a[1][6]  1
	b.push_back(0); 
	b.push_back(0);
	b.push_back(1);
	b.push_back(0);
	b.push_back(0);
	b.push_back(1);
	b.push_back(0);
	a.push_back(b);
	b.clear();
	//a[2][0]-a[2][6]  2
	b.push_back(0); 
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(0);
	b.push_back(1);
	a.push_back(b);
	b.clear();
	//a[3][0]-a[3][6]  3
	b.push_back(0); 
	b.push_back(1);
	b.push_back(1);
	b.push_back(0);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	a.push_back(b);
	b.clear();
	//a[4][0]-a[4][6]  4
	b.push_back(1); 
	b.push_back(0);
	b.push_back(1);
	b.push_back(0);
	b.push_back(0);
	b.push_back(1);
	b.push_back(1);
	a.push_back(b);
	b.clear();
	//a[5][0]-a[5][6]  5
	b.push_back(1); 
	b.push_back(1);
	b.push_back(0);
	b.push_back(0);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	a.push_back(b);
	b.clear();
	//a[6][0]-a[6][6]  6
	b.push_back(1); 
	b.push_back(1);
	b.push_back(0);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	a.push_back(b);
	b.clear();
	//a[7][0]-a[7][6]  7
	b.push_back(0); 
	b.push_back(1);
	b.push_back(1);
	b.push_back(0);
	b.push_back(0);
	b.push_back(1);
	b.push_back(0);
	a.push_back(b);
	b.clear();
	//a[8][0]-a[8][6]  8
	b.push_back(1); 
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	a.push_back(b);
	b.clear();
	//a[9][0]-a[9][6]  9
	b.push_back(1); 
	b.push_back(1);
	b.push_back(1);
	b.push_back(0);
	b.push_back(1);
	b.push_back(1);
	b.push_back(1);
	a.push_back(b);
	b.clear();
	//a[10][0]-a[10][6] first
	b.push_back(0);
	b.push_back(0);
	b.push_back(0);
	b.push_back(0);
	b.push_back(0);
	b.push_back(0);
	b.push_back(0);
	a.push_back(b);
	b.clear();

	for(int i=0;i