Python 输入坐标轴，获得象限转换

输入坐标轴，X轴，Y轴，判断该坐标在第几象限。然后根据象限以原点为中心。进行坐标的旋转。

import math
import numpy as np

# 逆时针旋转
def Nrotate(angle, valuex, valuey, pointx, pointy):
    valuex = np.array(valuex)
    valuey = np.array(valuey)
    nRotatex = (valuex - pointx) * math.cos(angle) - (valuey - pointy) * math.sin(angle) + pointx
    nRotatey = (valuex - pointx) * math.sin(angle) + (valuey - pointy) * math.cos(angle) + pointy
    return round(nRotatex, 2), round(nRotatey, 2)


# 顺时针旋转
def Srotate(angle, valuex, valuey, pointx, pointy):
    valuex = np.array(valuex)
    valuey = np.array(valuey)
    sRotatex = (valuex - pointx) * math.cos(angle) + (valuey - pointy) * math.sin(angle) + pointx
    sRotatey = (valuey - pointy) * math.cos(angle) - (valuex - pointx) * math.sin(angle) + pointy
    return sRotatex, sRotatey


pointx = -1
pointy = -1
# 判断，坐标轴在第几象限
if pointx > 0:
    if pointy > 0:
        xx = 1
    elif pointy < 0:
        xx = 4
elif pointx < 0:
    if pointy > 0:
        xx = 2
    else:
        xx = 3

# 第一象限保持不变
if xx == 1:
    # 参数(角度，要旋转的点，要绕的点)
    sPointx, sPointy = Srotate(math.radians(0), pointx, pointy, 0, 0)
    print(round(sPointx, 2), round(sPointy, 2))
# 第二象限顺时针旋转90度
if xx == 2:
    sPointx, sPointy = Srotate(math.radians(90), pointx, pointy, 0, 0)
    print(round(sPointx, 2), round(sPointy, 2))
# 第三象限顺时针旋转 180度
if xx == 3:
    sPointx, sPointy = Srotate(math.radians(180), pointx, pointy, 0, 0)
    print(round(sPointx, 2), round(sPointy, 2))
# 第四象限，逆时针旋转90度
if xx == 4:
    sPointx, sPointy = Nrotate(math.radians(180), pointx, pointy, 0, 0)
    print(round(sPointx, 2), round(sPointy, 2))