用C++语言计算1/(1*2)+1/(2*3)+...+1/(n*(n+1))

代码

#include
using namespace std;
int main()
{
	int n;
	double sum = 0;
	double a = 0;
	cout << "请输入n的值";
	cin >> n;
	for (double i = 1; i < n; i++)
	{
		a = 1 / (i * (i + 1));
		sum += a;
	}
	cout << "最终的值为：" << sum << endl;
	system("pause");
	return 0;
}

输出结果