注意广播的计算:
#coco #广播机制 import torch import numpy as np A = np.arange(0, 40, 10).reshape(4, 1) print(A) # [[ 0] # [10] # [20] # [30]] B = np.arange(0, 3) print(B) # [0 1 2] # 把ndarray转换为Tensor A1 = torch.from_numpy(A) # 形状为4x1 print(A1) # tensor([[ 0], # [10], # [20], # [30]], dtype=torch.int32) B1 = torch.from_numpy(B) # 形状为3 print(B1) # tensor([0, 1, 2], dtype=torch.int32) # Tensor自动实现广播 C = A1 + B1 print(C) # tensor([[ 0, 1, 2], # [10, 11, 12], # [20, 21, 22], # [30, 31, 32]], dtype=torch.int32) # 我们可以根据广播机制,手工进行配置 # 根据规则1,B1需要向A1看齐,把B变为(1,3) B2 = B1.unsqueeze(0) # B2的形状为1x3 print(B2) # tensor([[0, 1, 2]], dtype=torch.int32) # 使用expand函数重复数组,分别的4x3的矩阵 A2 = A1.expand(4, 3) print(A2) # tensor([[ 0, 0, 0], # [10, 10, 10], # [20, 20, 20], # [30, 30, 30]], dtype=torch.int32) B3 = B2.expand(4, 3) print(B3) # tensor([[0, 1, 2], # [0, 1, 2], # [0, 1, 2], # [0, 1, 2]], dtype=torch.int32) # 然后进行相加,C1与C结果一致 C1 = A2 + B3
做不到的话,就做到能做到为止;做到后,就继续做到完美为 止;做到完美之后,就继续做到无论做几次都能完美为止。
——羽生结弦



