利用二叉树模板类构造函数 由前序遍历和中序遍历构建二叉树（C++）

结果输出

#include
using namespace std;
struct Node {
public:
    char data;
    Node* left;
    Node* right;
    Node() {
        left = NULL;
        right = NULL;
    }
    Node(char ch, Node* left, Node* right) {
        this->data = ch;
        this->left = left;
        this->right = right;
    }
};

//二叉树的前序遍历
void preOrder(Node* root) {
    if (root == NULL) {
        return;
    }
    cout << root->data << " ";
    preOrder(root->left);
    preOrder(root->right);
}
//二叉树的中序遍历
void midOrder(Node* root) {
    if (root == NULL) {
        return;
    }
    midOrder(root->left);
    cout << root->data << " ";
    midOrder(root->right);
}

//由前序遍历和中序遍历构建二叉树
Node* buildTree(char* pre, char* in, int n) {

    if (n == 0) {
        return NULL;
    }
    Node* root = new Node();
    root->data = *pre;
    char* p;
    //在中序中找到根节点
    for (p = in; p < in + n; p++) {
        if (*p == *pre) {
            break;
        }
    }
    int left = p - in;//左子树个数
    int right = n - left - 1;//右子树个数
    //递归构建左子树
    root->left = buildTree(pre + 1, in, left);
    //递归构建右子树
    root->right = buildTree(pre + left + 1, p + 1, right);
    return root;
}
//二叉树
class BinTree {
protected:
    int _size;
    Node* _root;
public:
    BinTree(char* pre, char* in, int n) { _root=buildTree(pre, in, n); }
    Node* get_root() { return _root; }
};
int main() {
    char pre[] = "idcabhfeglkjnmpo";
    char in[] = "abcdefghijklmnop";
    cout << "已知前序遍历:";
    for (auto i : pre) cout << i << " "; cout << endl;
    cout << "已知后序遍历:";
    for (auto i : in) cout << i << " "; cout << endl;
    int length = sizeof(pre) - 1;
    BinTree tree=BinTree(pre, in, length);
    Node* root = tree.get_root();
    cout << "======对生成的二叉树进行遍历======" << endl;
    //使用先序遍历和中序遍历验证构建的二叉树是否正确
    cout << "先序遍历:"; preOrder(root); cout<