Math类中全部是静态方法，都可以用ClassName.funName（）
字段 double E 自然对数e double PI 圆周率三角函数 cos()余弦
参数是弧度。 弧度= 2 Math.PI /360 * 度数 比如：60度 = 2 * Math.PI / 360 * 60 cos(60度) Math.cos( 1.0/3 * Math.PI) = 0.5sin()正弦
sin(30度) Math.sin(1.0 / 6 * Math.PI) = 0.5tan()正切
tan(45度) Math.tan(1.0 /4 * Math.PI) = 1acos()反余弦
acos(0.5) = Math.acos(0.5) / Math.PI * 180 = 60度asin()反正弦
asin(0.5) = Math.asin(0.5) / Math.PI * 180 = 30度atan()反正切
atan(1) = Math.atan(1.0) / Math.PI * 180 = 45度角度转换 toDegrees()将弧度转为角度
System.out.println(Math.toDegrees(Math.PI)); //180toRadians()将角度转弧度
System.out.println(Math.toRadians(180)); //3.141592653589793求幂，开方，指数，对数 hypot(x,y) 返回x平方+y平方再求开方
经典的勾三股四弦五 System.out.println(Math.hypot(3, 4)); //5.0 sqrt(3^2 + 4^2)cbrt(x)返回x的立方根
System.out.println(Math.cbrt(27)); //3.0sprt(x)返回x的平方根
System.out.println(Math.sqrt(4)); //2.0scalb(x,y)返回 x * 2^y
System.out.println(Math.scalb(1.344, 2)); // 1.344 * 2^2 = 5.376exp(x) 自然数e的x次方
System.out.println(Math.exp(2.0)); //7.38905609893065 e^2pow(x,y)返回x的y次幂
System.out.println(Math.pow(2, 3)); //8.0expm1()自然数e的x次方减1
System.out.println(Math.expm1(2.0)); //6.38905609893065log1p(x) 求x + 1 以e为底的对数
System.out.println(Math.log1p(1.718281828459045)); //1.0log(x)求x以e为底的对数
System.out.println(Math.log(2.718281828459045));log10(x)求x以10为底的对数
System.out.println(Math.log10(10)); //1.0getExponent(x)返回以2为底x的指数
System.out.println(Math.getExponent(1024)); //10取整、取模四舍五入 ceil()向上取整
System.out.println(Math.ceil(3.6)); //4.0 System.out.println(Math.ceil(3.4)); //4.0floor()向下取整
System.out.println(Math.floor(3.5)); //3.0floor(x,y) x除于y的值再向下取整
System.out.println(Math.floorDiv(10, 4)); //2floorMod(x,y)返回x对y取模
System.out.println(Math.floorMod(4, 2)); //0 System.out.println(Math.floorMod(3, 2)); //1rint()向靠近的数取整
System.out.println(Math.rint(2.5)); //2.0 System.out.println(Math.rint(2.4)); //2.0 System.out.println(Math.rint(2.6)); //3.0 System.out.println(Math.rint(-2.6)); //-3.0 System.out.println(Math.rint(-2.5)); //-2.0 System.out.println(Math.rint(-2.4)); //-2.0round() 四舍五入（负数有些和我们平常的不一样）
System.out.println(Math.round(2.6)); //3 System.out.println(Math.round(2.5)); //3 System.out.println(Math.round(2.4)); //2 System.out.println(Math.round(-2.6)); //-3 System.out.println(Math.round(-2.5)); //-2 System.out.println(Math.round(-2.4)); //-2返回加工后的数 abs()取绝对值
System.out.println(Math.abs(-1)); // 1 System.out.println(Math.abs(-1.1F)); // 1.1 System.out.println(Math.abs(-1L)); // 1 System.out.println(Math.abs(-1.0)); // 1.0copySing(x,y)用y的符号返回第一个数的值
System.out.println(Math.copySign(0.5, -1.0)); //-0.5
System.out.println(Math.copySign(0.5f, 1.0f)); //0.5
random()返回一个0-1之间的随机小数
for (int i = 0; i < 10; i++) {
System.out.println(Math.random());
}
// 0.9072383311558234
// 0.7659940574619751
// 0.7978623317262958
// 0.38447672747439443
// ...
signum返回大于0则为1，等于0为0，小于0为-1
System.out.println(Math.signum(2.0)); //1.0 System.out.println(Math.signum(0.5)); //1.0 System.out.println(Math.signum(0)); // 0.0 System.out.println(Math.signum(-1)); // -1.0toIntExact()将Long类型截取最大的Int类型
System.out.println(Math.toIntExact(32134234312312321L));//321342343nextAfter(x,y)返回x以y方向最相近的数
-------2.5---->3.6--- -----3.6<------4.5--- System.out.println(Math.nextAfter(2.5, 3.6)); //2.5000000000000004 System.out.println(Math.nextAfter(4.5, 3.6)); //4.499999999999999nextDown()、nextUp()返回以负无穷/正无穷大方向的最相近的数
----负无穷<----1.2233--- ----1.2233---->正无穷--- System.out.println(Math.nextDown(1.2233)); //1.2232999999999998 System.out.println(Math.nextUp(1.2233)); //1.2233000000000003返回一个或两个数之间的操作 decrementExact()返回一个减1的数超过返回则会报错
System.out.println(Math.decrementExact(-1));
System.out.println(Math.decrementExact(-2147483648)); //报异常
incrementExact()返回一个增1的数超过返回则会报错
System.out.println(Math.incrementExact(2147483647)); //报异常multiplyExact(x,y)返回x*y超出范围则报异常
System.out.println(Math.multiplyExact(3, 4)); //12
System.out.println(Math.multiplyExact(3, 2147483647)); //报错
subtractExact(x,y)返回x-y,超出范围报错
System.out.println(Math.subtractExact(3, 4)); //-1
System.out.println(Math.subtractExact(3, 3)); //0
System.out.println(Math.subtractExact(3, 2)); //1
System.out.println(Math.subtractExact(-2, 2147483647)); //报异常 ArithmeticException
addExact(x,y)返回两数之和，超过范围则会报相应的错误
System.out.println(Math.addExact(2147483647, 23)); //Exception in thread "main" java.lang.ArithmeticException: integer overflow System.out.println(Math.addExact(9223372036854775807L, 1L)); //Exception in thread "main" java.lang.ArithmeticException: long overflownegateExact(x)对x取反超出范围则报错
System.out.println(Math.negateExact(2147483647)); //-2147483647 System.out.println(Math.negateExact(-2147483647)); //2147483647 System.out.println(Math.negateExact(-2147483648)); //报错最小最大值 max(x,y)求两数中最大的数
System.out.println(Math.max(3, 4)); //4 System.out.println(Math.max(-3, -4)); //-3 System.out.println(Math.max(Math.abs(-3), 4)); //4min(x,y)求两数中最小的数
System.out.println(Math.min(3, 4)); //3 System.out.println(Math.min(-3, -4)); //-4 System.out.println(Math.min(Math.abs(-3), 4)); //3
