解题思路
首先获取数字的长度，然后根据3种情况创建3个函数（长度=3，长度=2，长度=1），最后调用函数输出。
获取数字长度
def lennum(num):
n = len(num)return n
长度为3时调用的函数
def Bnum(num):
Bai = 'B' * int(num[0])Shi = 'S' * int(num[1])
Ge = ''
for i in range(1,int(num[2]) + 1)
Ge += str(i)
sumstr = Bai + Shi + Ge
return sumstr
长度为2时调用的函数
def Snum(num):
Shi = 'S' * int(num[0])
Ge = ''
for i in range(1,int(num[1]) + 1)
Ge += str(i)
sumstr = Shi + Ge
return sumstr
长度为1时调用的函数
def Gnum(num):
Ge = ''
for i in range(1,int(num[0]) + 1)
Ge += str(i)
return Ge
将他们连在一起得到
def lennum(num):
n = len(num)return n
def Bnum(num):
Bai = 'B' * int(num[0])Shi = 'S' * int(num[1])
Ge = ''
for i in range(1,int(num[2]) + 1)
Ge += str(i)
sumstr = Bai + Shi + Ge
return sumstr
def Snum(num):
Shi = 'S' * int(num[0])
Ge = ''
for i in range(1,int(num[1]) + 1)
Ge += str(i)
sumstr = Shi + Ge
return sumstr
def Gnum(num):
Ge = ''
for i in range(1,int(num[0]) + 1)
Ge += str(i)
return Ge
num = input()
n = lennum(num)
if n == 3:
print(Bnum(num))
if n == 2:
print(Snum(num))
else:
print(Gnum(num))
总结
我想还有更简单便捷的方法
但是我目前想不到
未来应当巩固基础
