长键输入 python

首先没有考虑到双指针，主要是 if 条件的判断，没有想到 typed 重复中和前一个对比，还有，即使自己重写一遍也缺少了一些判断条件 ：

1> 有 i-1，要考虑 i>0

2> np.array([1,2,3])=[1 2 3]

参考答案是

name = "laiden"
typed = "aidden"
l1, l2 = len(name), len(typed)
i, j, a = 0, 0, 0
while j < l2:
    if i < l1 and name[i] == typed[j]:
        i += 1
        j += 1
    elif j > 0 and typed[j] == typed[j - 1]:
        j += 1
    else:
        a += 1
        break
if a == 0:
    print("True")
else:
    print("False")

我的代码用了两个 for，想数相同字母的个数，然后做差，有一个负数就是错误，但是有点长

import numpy as np
name = "laiden"
typed = "laiden"
n1, n2 = [], []
a, b, d = 1, 1, 0
name1 = list(name)
typed1 = list(typed)
for i in range(len(name1)-1):
    if name1[i] == name1[i + 1]:
        a += 1
    else:
        n1.append(a)
        a = 1
for j in range(len(typed1)-1):
    if typed1[j] == typed1[j + 1]:
        b += 1
    else:
        n2.append(b)
        b = 1
c = np.array(n2) - np.array(n1)
for k in c:
    if k < 0:
        d += 1
if d > 0:
    print("False")
else:
    print("True")