Java语言程序设计 例题 3.3（解2×2线性方程）

*3.3（Algebra:solve 2×2linear equations）A linear equation can be solved using Crame's rule given in Programming Exercise 1.13 .Write a program that prompts the user to enter a,b,c,d,e,and,f and displays the result. If ad- bc is 0,report that "The equation has no solution."

*3.3 (代数：解2×2线性方程）线性方程可以用编程练习1.13给出的克莱默法则求解.编写一个提示程序使用户输入a,b,c,d,e和f，并显示结果.如果ad-bc为0，则报告"The equation has no solution."

代码如下：

import java.util.Scanner;
public class Unite3Test3 {
	public static void main(String[] args) 
	{
		Scanner scan=new Scanner(System.in);
		System.out.println("请输入a的值：");
		double a=scan.nextDouble();
		System.out.println("请输入b的值：");
		double b=scan.nextDouble();
		System.out.println("请输入c的值：");
		double c=scan.nextDouble();
		System.out.println("请输入d的值：");
		double d=scan.nextDouble();
		System.out.println("请输入e的值：");
		double e=scan.nextDouble();
		System.out.println("请输入f的值：");
		double f=scan.nextDouble();
		double x=(e*d-b*f)/(a*d-b*c);
		double y=(a*f-e*c)/(a*d-b*c);
		if(a*d-b*c==0) 
		{
			System.out.println("The equation has no solution.");
		}else
		{
			System.out.println("x is"+x+"and"+"y is"+y);
		}
			
	}
}

 运行结果如下：