刷题自用0513
代码class Solution {
public:
vector reversePrint(ListNode* head) {
vector res;
while(head){
res.push_back(head->val);
head=head->next;
}
reverse(res.begin(),res.end());
return res;
}
};
思路
遍历链表,把val依次存入res中,最后反转res,得到从尾到头的res,最后输出得到结果



