方法一：Iterator迭代器
val list = arrayListOf("1", "2", "3", "4", "5", "6")
val iterator = list.iterator()
while (iterator.hasNext()){
if (iterator.next() == "4"){
iterator.remove()
}
}
println("result: $list") //result: [1, 2, 3, 5, 6]
方法二：for循环
val list = arrayListOf("1", "2", "3", "4", "5", "6")
for (index in list.size - 1 downTo 0){
if (list[index] == "3") {
list.removeAt(index)
}
}
println("result: $list") //result: [1, 2, 4, 5, 6]
方法三：removeIf
val list = arrayListOf("1", "2", "3", "4", "5", "6")
//minSdkVersion >= 24(N)
list.removeIf {
it == "5"
}
println("result: $list") //result: [1, 2, 3, 4, 6]
方法四：removeAll + filter
val list = arrayListOf("1", "2", "3", "4", "5", "6")
list.removeAll(list.filter {
it == "2"
})
println("result: $list") //result: [1, 3, 4, 5, 6]
