C++实现nfc数据还原

#include "stdafx.h"
#include 
#include 


using namespace std;

void hexToBinary(int a);
void dataExchange(int a[]);

int datas[8];

int main()
{
	hexToBinary(0xd1);

	int a[] = { 0xd1,0x01,0x0F,0x54,0x02,0x65,0x6E, 0x68,0x65,0x6c,0x6c,0x6F,0x2c,0x77,0x6F,0x72 ,0x6c ,0x64 ,0x21 };
	int b[] = { 0xD1 ,0x01 ,0x09 ,0x55 ,0x01 ,0x2E,0x6E ,0x66 ,0x63 ,0x2E ,0x63 ,0x6F ,0x6D };

	dataExchange(a);
	cout << "---------------------------------------------" << endl;
	dataExchange(b);
}

//-------------将hex转二进制值

void hexToBinary(int a)
{
	int n = 8;

	int sn = -1;

	for (int i = n - 1; i >= 0; i--)
	{
		int c = (a & 1 << i) >> i;

		if (c == 1)
		{
			sn = 1;
		}

		if (sn == 1)
		{
			datas[n - i - 1] = c;
		}

	}

}

//-----------数据处理

void dataExchange(int a[])    //-------------  d1 01 0F 54 02 65 6E 68 65 6c 6F 2c 77 6F 72 6c 64 21
{
	hexToBinary(a[0]);  //得到datas  0-7 分别对应  mb me cf sr i l inf

	int len = -1;

	if (datas[0] == 1 && datas[1] == 1)
	{
		if (datas[2] == 1)
		{
			cout << "分块情况暂不考虑！" << endl;
			return;
		}

		if (datas[3] == 1)  //--------payload长度
		{
			len = 1;
		}
		else
		{
			len = 4;
		}

		if (datas[4] == 1 || datas[5] == 1)
		{
			cout << "有 id 字段或 id length 字段的情况不考虑！";
			return;
		}

		if (datas[7] == 1)  //----------------tnf
		{
			//---------判断是网址型还是文本型

			int charLen1 = 2 + len;   //------3
			char s = a[charLen1] - '';

			if (s == 'U')
			{
				string s;

				switch (a[charLen1 + 1])
				{
				case 0:
					break;
				case 1:

					s = "http://www";

					break;
				case 2:

					s = "https://www";

					break;
				case 3:

					s = "http://";

					break;
				case 4:

					s = "https://";

					break;
				case 5:

					s = "tel:";

					break;
				case 6:

					s = "mailto:";

					break;
				case 7:

					s = "htp://anonymous:anonymous@";

					break;

				case 8:

					s = "ftp://ftp.";

					break;
				case 9:

					s = "ftps://";

					break;
				}

				int start = charLen1 + 2;

				int dataLen = a[2] - 1;

				cout << "该数据为网址型，内容为：" << s;
				for (int i = start; i < start + dataLen; i++)
				{
					char temp = a[i] - '';
					cout << temp;
				}
				cout << endl;
			}

			if (s == 'T')
			{
				//-----------语言码长度

				int languageLen = a[charLen1 + 1];   //-------------4   02
				int start = charLen1 + 2 + languageLen;   //   -----3 2 
				int dataLen = a[2] - (1 + languageLen);

				//---------语言码内容 

				int s = charLen1 + 1 + 1;
				cout << "该数据为文本型，语言码内容为：";
				for (int i = s; i < s + languageLen; i++)
				{
					char temp = a[i] - '';
					cout << temp;
				}
				cout << endl;

				cout << "实际内容为：";
				for (int i = start; i < dataLen + start; i++)
				{
					char temp = a[i] - '';
					cout << temp;
				}
				cout << endl;
			}
		}
	}

}