A1067 Sort with Swap(0, i)（25分）PAT甲级 (Advanced Level) Practice（C++）满分题解【swap排序】

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Input Specification:
Each input file contains one test case, which gives a positive N (≤105) followed by a permutation sequence of {0, 1, ..., N−1}. All the numbers in a line are separated by a space.

Output Specification:
For each case, simply print in a line the minimum number of swaps need to sort the given permutation.

Sample Input:

10
3 5 7 2 6 4 9 0 8 1

Sample Output:

代码如下：

#include
using namespace std;
int a[100010];//数字i所在的位置
int main()
{
    int n,t,count=0;
    cin>>n;
    for(int i=0;i>t;
        a[t]=i;//数字t在第i个位置上
    }
    for(int i=0;i 
运行结果如下：

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A1067 Sort with Swap(0, i)（25分）PAT甲级 (Advanced Level) Practice（C++）满分题解【swap排序】

Input Specification:
Each input file contains one test case, which gives a positive N (≤105) followed by a permutation sequence of {0, 1, ..., N−1}. All the numbers in a line are separated by a space.

Output Specification:
For each case, simply print in a line the minimum number of swaps need to sort the given permutation.

Sample Input:
10 3 5 7 2 6 4 9 0 8 1

Sample Output:
9
代码如下：
#include using namespace std; int a[100010];//数字i所在的位置 int main() { int n,t,count=0; cin>>n; for(int i=0;i>t; a[t]=i;//数字t在第i个位置上 } for(int i=0;i 运行结果如下：

C/C++/C#相关栏目本月热门文章

A1067 Sort with Swap(0, i)（25分）PAT甲级 (Advanced Level) Practice（C++）满分题解【swap排序】

Input Specification: Each input file contains one test case, which gives a positive N (≤105) followed by a permutation sequence of {0, 1, ..., N−1}. All the numbers in a line are separated by a space.

Output Specification: For each case, simply print in a line the minimum number of swaps need to sort the given permutation.

Sample Input: 10 3 5 7 2 6 4 9 0 8 1

Sample Output: 9 代码如下： #include using namespace std; int a[100010];//数字i所在的位置 int main() { int n,t,count=0; cin>>n; for(int i=0;i>t; a[t]=i;//数字t在第i个位置上 } for(int i=0;i 运行结果如下：

C/C++/C#相关栏目本月热门文章

Input Specification:
Each input file contains one test case, which gives a positive N (≤105) followed by a permutation sequence of {0, 1, ..., N−1}. All the numbers in a line are separated by a space.

Output Specification:
For each case, simply print in a line the minimum number of swaps need to sort the given permutation.

Sample Input:
10 3 5 7 2 6 4 9 0 8 1

Sample Output:
9
代码如下：
#include using namespace std; int a[100010];//数字i所在的位置 int main() { int n,t,count=0; cin>>n; for(int i=0;i>t; a[t]=i;//数字t在第i个位置上 } for(int i=0;i 运行结果如下：