Python编程实现将列表s=[2, 4, 2, 3, 1, 2, 3, 4 ,5, 8, 4, 3]中的偶数变为它的平方，奇数保持不变。

s = [2, 4, 3, 1, 2, 3, 4, 5, 8, 4, 3]
print("变换前：", s)
for i in range(0, len(s)):
    if s[i] % 2 == 0: #s[i]为对应s列表中下标为i的元素
        s[i] = s[i]*s[i]
print("变换后：", s)
# 运行效果如下：
变换前： [2, 4, 3, 1, 2, 3, 4, 5, 8, 4, 3]
变换后： [4, 16, 3, 1, 4, 3, 16, 5, 64, 16, 3]

变换前： [2, 4, 3, 1, 2, 3, 4, 5, 8, 4, 3]
变换后： [4, 16, 3, 1, 4, 3, 16, 5, 64, 16, 3]