用二分法求方程2x^3-4x^2+3x-6=0在(-10, 10)之间的根。
#include#include int main() { float x0, x1, x2, fx0, fx1, fx2; do { printf("请输入x1,x2的值: "); scanf("%f,%f", &x1, &x2); fx1 = 2 * x1 * x1 * x1 - 4 * x1 * x1 - 3 * x1 - 6; fx2 = 2 * x2 * x2 * x2 - 4 * x2 * x2 - 3 * x2 - 6; } while (fx1 * fx2 > 0); do { x0 = (x1 + x2) / 2; fx0 = 2 * x0 * x0 * x0 - 4 * x0 * x0 - 3 * x0 - 6; if (fx0 * fx1 <= 0)// { x2 = x0;//更新右端点 fx2 = fx0;//更新右端点函数值 } else { x1 = x0;//更新左端点 fx1 = fx0; } } while (fabs(fx0) >= 1e-6);//函数值无线接近于0(浮点数不能与整数比较) printf("方程的根=%6.2fn", x0); return 0; }



