输入密码,有三次机会,三次都不对显示机会已用完。
#include#include int main() { //输入密码,三次机会 char word[20] = { 0 }; char dui[20] = "snareli";//正确密码为snareli int i = 1; printf("please input password:"); while (i <= 3) { printf("please input password:"); scanf_s("%s", word, 20); if (strcmp(word, dui) == 0) { printf("correctn"); break; } else printf("non"); i++; } if (i == 4) printf("no chancen"); return 0; }



