C语言，输入年月日，返回总天数，可改写成打印一个月中的假期天数。

#include
#include
#include
#define AS 12
#define QW 20
#define SS 7
struct as {
	char w[AS];
};
struct qw {
	int q;
	int h;
	int o;
};
struct yu {
	char* s[2];
	char aa[2];
};
void qq(void);
int gg(struct as v, struct qw r);
void jj(struct yu z, struct qw y);
int main(void)
{
	double b;
	double n;
	struct qw e;
	char* k, * l;
	struct as y = { {31,28,31,30,31,30,31,31,30,31,30,31} };
	char m[AS] = "元旦假期：";
	char mm[AS] = "除夕假期：";
	l = mm;
	k = m;
	struct yu yi = { {k,l},{3,1} };
	while (1)
	{
		printf("请输入年份：");
		scanf_s("%d", &e.q);
		if (e.q ==0)
		{
			printf("退出程序。");
			exit(EXIT_FAILURE);
		}
		printf("请输入月份：");
		scanf_s("%d", &e.h);
		while ((e.h > 12) || (e.h <= 0))
		{
			printf("月份输入错误！");
			printf("请重新输入：");
			scanf_s("%d", &e.h);
		}
		printf("请输入日期：");
		scanf_s("%d", &e.o);
			while ((e.o > y.w[e.h-1])||(e.o<=0))
			{
				printf("日期输入错误！");
				printf("请重新输入：");
				scanf_s("%d", &e.o);
			}
		b = gg(y, e);
		n = b / SS;
		printf("从去年12月31日至今已过 %.f 天，大约 %.2f 个星期。n", b, n);
		if (e.h == 1)
		{
			jj(yi, e);
		}
		if (b == 365)
		{
			printf("新的一年即将到来，新年新气象，祝你新年元气满满！！n");
		}
		if ((e.h == 5) && (e.o == 1))
		{
			printf("五一劳动节快乐，祝你节日快乐！n");
		}
		puts("祝你生活快乐，开心面对每一天！");
		printf("n");
	}
	return 0;
}
void qq(void)
{
	while (getchar() != 'n')
		continue;
}
int gg(struct as v, struct qw r)
{
	int u = 0;
	if (r.h > 1)
	{
		for (int a = 0; a < r.h-1; a++)
		{
			u += v.w[a];
		}
	}
	u += r.o;
	return u;
}
void jj(struct yu z, struct qw y)
{
	printf("在 %d 月中假期：", y.h);
	printf("%s假期有 %d 天！ ", z.s[0], z.aa[0]);
	printf("%s假期有 %d 天！n", z.s[1], z.aa[1]);
	printf("1月假期一共有 %d 天n", z.aa[0] + z.aa[1]);
}