java 获取括号外无规则位置数据

public static void main(String[] args) {
        String str = "(11)220219(17)230813(10)0122010313(21)2222030178";
        String regex = "(\([^\)]*\))";
        List list = new ArrayList<>();
        list = getSubUtil(str, regex);
        System.out.println(list);
        for (int i = 0; i < list.size(); i++) {
            System.out.println(list.get(i));
            if (i == (list.size() - 1)) {
                System.out.println(str.substring(str.indexOf(list.get(i))+4));
            } else {
                System.out.println(str.substring(str.indexOf(list.get(i)) + 4, str.lastIndexOf(list.get(i + 1))));
            }
        }

    }

    
    public static List getSubUtil(String soap, String rgex) {
        List list = new ArrayList();
        Pattern pattern = Pattern.compile(rgex);// 匹配的模式
        Matcher m = pattern.matcher(soap);
        while (m.find()) {
            int i = 1;
            list.add(m.group(i));
            i++;
        }
        return list;
    }