~~~笔锋至此又怎能平淡而终,故事开始便不承认普通✌✌✌
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题目:
解题思路:
>判断子缀和是否小于0 >如果成立则为不合法序列
代码实现:
#includeusing namespace std; void Judge(string s) { int sum = 0; for (int i = 0; i < s.length(); i++) { if (s[i] == 'I') { sum += 1; } else { sum -= 1; } if (sum < 0) { cout << "不合法序列" << endl; return; } } if (sum == 0) { cout << "合法序列" << endl; return; } cout << "不合法序列" << endl; } int main() { string s1 = "IOIIOIOO"; string s2 = "IOOIOIIO"; string s3 = "IIIOIOIO"; string s4 = "IIIOOIOO"; Judge(s1); Judge(s2); Judge(s3); Judge(s4); }



