import numpy as np
k = np.matrix([[1, 2, 3, 4],
[5, 6, 7, 8],
[9, 10, 11, 12]])
print(np.shape(k)) # 输出（3，4）表示矩阵为3行4列
print(k.shape[0]) # shape[0]输出3，为矩阵的行数
print(k.shape[1]) # 同理shape[1]输出列数
![python中shape[0]与shape[1]](http://www.mshxw.com/aiimages/31/833403.png "python中shape[0]与shape[1]")
import numpy as np
k = np.matrix([[1, 2, 3, 4],
[5, 6, 7, 8],
[9, 10, 11, 12]])
print(np.shape(k)) # 输出（3，4）表示矩阵为3行4列
print(k.shape[0]) # shape[0]输出3，为矩阵的行数
print(k.shape[1]) # 同理shape[1]输出列数
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