思路:时间戳取(24*60*60)余,得出时间戳在当日的第多少秒,根据起始与终止时间先后顺序,进行判断
public static boolean isCrossDay(long date, long startTime, long endTime) throws ParseException {
date = date %(24*60*60*1000);
startTime = startTime%(24*60*60*1000);
endTime = endTime%(24*60*60*1000);
if (startTime < endTime) {
return startTime < date && endTime > date;
}else {
return endTime < date || startTime > date;
}
}



