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C语言的三子棋,用22天总结了一份完美的SQL学习笔记

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C语言的三子棋,用22天总结了一份完美的SQL学习笔记

}

else

{

printf(“该输入的坐标已经被占用n”);

}

}

else

{

printf(“输入坐标错误n”);

}

}

}

[](()电脑下棋


电脑设置两个随机值,再将进行条件判断

void ComputerMove(char board[ROW][COL], int row, int col)

{

printf(“电脑走>n”);

while (1)

{

int x = rand() % row;

int y = rand() % col;

if (board[x][y] == ’ ')

{

board[x ][y ] = ‘#’;

break;

}

}

}

[](()三子棋的判断胜负


是否有3个"@“能否连接成一条直线如果有则玩家获胜,是否有3个”#"能否连接成一条直线如果有则玩家获胜,如果棋盘已满没有获得胜利则为平均。

int IsFull(char board[ROW][COL], int row, int col)

{

int i = 0;

int j = 0;

for (i = 0; i < row; i++)

{

for (j = 0; j < col; j++)

{

if (board[i][j] == ’ ')

{

return 0;

}

}

}

return 1;

}

char IsWin(char board[ROW][COL], int row, int col)

{

int i = 0;

for (i = 0; i < row; i++)

{

if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ’ ')

{

return board[i][0];

}

}

for (i = 0; i < col; i++)

{

if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != ’ ')

{

return board[0][i];

}

}

if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ’ ')

return board[1][1];

if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ’ ')

return board[1][1];

if (IsFull(board, row, col))

{

return ‘Q’;

}

return ‘C’;

}

[](()总代码


#pragma once

#include

#include

#include

#define ROW 3

#define COL 3

//初始化棋盘

void InitBoard(char board[ROW][COL], int row, int col);

//打印棋盘

void DisplayBoard(char board[ROW][COL], int row, int col);

//玩 《一线大厂Java面试题解析+后端开发学习笔记+最新架构讲解视频+实战项目源码讲义》开源 家下棋

void PlayerMove(char board[ROW][COL], int row, int col);

//电脑下棋

void ComputerMove(char board[ROW][COL], int row, int col);

//判断游戏的输赢

char IsWin(char board[ROW] Java开源项目【ali1024.coding.net/public/P7/Java/git】 [COL], int row, int col);

void InitBoard(char board[ROW][COL], int row, int col)

{

for (int i = 0; i < row; i++)

{

int j = 0;

for (j = 0; j < col; j++)

{

board[i][j] = ’ ';

}

}

}

void DisplayBoard(char board[ROW][COL], int row, int col)

{

int i = 0;

for (i = 0; i < row; i++)

{

int j = 0;

for (j = 0; j < col; j++)

{

printf(" %c ", board[i][j]);

if (j < col - 1)

printf(“|”);

}

printf(“n”);

if (i < row - 1)

{

for (j = 0; j < col; j++)

{

printf(“—”);

if (j < col - 1)

printf(“|”);

}

}

printf(“n”);

}

}

void PlayerMove(char board[ROW][COL], int row, int col)

{

int x = 0;

int y = 0;

while (1)

{

printf(“请选择第三子棋坐标>”);

scanf(“%d%d”,&x,&y);

if ((x >= 1 && x <= row) && (y >= 1 && y <= col))

{

if (board[x - 1][y - 1] == ’ ')

{

board[x - 1][y - 1] = ‘@’;

break;

}

else

{

printf(“该输入的坐标已经被占用n”);

}

}

else

{

printf(“输入坐标错误n”);

}

}

}

void ComputerMove(char board[ROW][COL], int row, int col)

{

printf(“电脑走>n”);

while (1)

{

int x = rand() % row;

int y = rand() % col;

if (board[x][y] == ’ ')

{

board[x ][y ] = ‘#’;

break;

}

}

}

int IsFull(char board[ROW][COL], int row, int col)

{

int i = 0;

int j = 0;

for (i = 0; i < row; i++)

{

for (j = 0; j < col; j++)

{

if (board[i][j] == ’ ')

{

return 0;

}

}

}

return 1;

}

char IsWin(char board[ROW][COL], int row, int col)

{

int i = 0;

for (i = 0; i < row; i++)

{

if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ’ ')

{

return board[i][0];

}

}

for (i = 0; i < col; i++)

{

if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != ’ ')

{

return board[0][i];

}

}

if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ’ ')

return board[1][1];

if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ’ ')

return board[1][1];

最后总结

搞定算法,面试字节再不怕,有需要文章中分享的这些二叉树、链表、字符串、栈和队列等等各大面试高频知识点及解析

最后再分享一份终极手撕架构的大礼包(学习笔记):分布式+微服务+开源框架+性能优化

= board[2][i] && board[0][i] != ’ ')

{

return board[0][i];

}

}

if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ’ ')

return board[1][1];

if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ’ ')

return board[1][1];

最后总结

搞定算法,面试字节再不怕,有需要文章中分享的这些二叉树、链表、字符串、栈和队列等等各大面试高频知识点及解析

最后再分享一份终极手撕架构的大礼包(学习笔记):分布式+微服务+开源框架+性能优化

[外链图片转存中…(img-7VZQZtmi-1650617123860)]

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