LeetCode-128. Longest Consecutive Sequencehttps://leetcode.com/problems/longest-consecutive-sequence/
Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n) time.
Example 1:
Input: nums = [100,4,200,1,3,2] Output: 4 Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1] Output: 9
Constraints:
- 0 <= nums.length <= 10^5
- -10^9 <= nums[i] <= 10^9
class Solution {
public:
int longestConsecutive(vector& nums) {
unordered_set hash;
for (const int & num: nums) {
hash.insert(num);
}
int ans = 0;
while (!hash.empty()) {
int cur = *(hash.begin());
hash.erase(cur);
int next = cur + 1, prev = cur - 1;
while (hash.count(next)){
hash.erase(next++);
}
while (hash.count(prev)) {
hash.erase(prev--);
}
ans = max(ans, next - prev - 1);
}
return ans;
}
};
【Java】
class Solution {
public int longestConsecutive(int[] nums) {
HashSet set=new HashSet();
int maxLen =0;
for(int k :nums){
set.add(k);
}
for(int i=0; i


![LeetCode-128. Longest Consecutive Sequence [C++][Java] LeetCode-128. Longest Consecutive Sequence [C++][Java]](http://www.mshxw.com/aiimages/31/820997.png)
