现在要对上面数据进行分组，获取统计结果：
实现方式一：
-- ================================================-- Description:合并分组内容-- Author:夏保华-- Date:2009-08-06-- ================================================create table Employees(DepartmentName varchar(50),EmpoyeeName varchar(20)) insert into Employees select '开发部','小刘' union allselect '开发部','小王' union allselect '开发部','小张' union allselect '工程部','老吴' union allselect '工程部','老李' union allselect '市场部','大兵' union allselect '市场部','大黄' union allselect '市场部','大虾' union allselect '市场部','大国'go create function Sum_ByGroup(@DepartmentName varchar(50)) returns varchar(8000) as begin declare @ret varchar(8000) set @ret = '' select @ret = @ret+','+EmpoyeeName from Employees where DepartmentName = @DepartmentName set @ret = stuff(@ret,1,1,'') return @ret end goselect DepartmentName,dbo.Sum_ByGroup(DepartmentName) as EmployeesList from Employeesgroup by DepartmentNamego
实现方式二：利用 T-SQL 技术生成 XML 的方法
select DepartmentName,stuff((select ','+EmpoyeeName from Employees where DepartmentName = e.DepartmentName for xml path('')),1,1,'') as EmployeesList from Employees Egroup by DepartmentName 呵呵，这样就是不是简单多了，不用再写一个函数去处理这么麻烦了。 扩展：For XML Path
1.在该 XML 中，生成的行集中的每个列值都包在元素中。由于 SELECt 子句未指定任何列名别名，因此生成的子元素名称与 SELECT 子句中相应的列名相同。如果未对path指定任何信息，针对行集中的每一行，将添加一个
SQL语句：
select DepartmentName,(select ''+EmpoyeeName from Employees where DepartmentName = e.DepartmentName for xml path) as EmployeesList from Employees Egroup by DepartmentName
如：
2.您可以选择指定行元素名称，以覆盖默认的
SQL语句：
select DepartmentName,(select ''+EmpoyeeName from Employees where DepartmentName = e.DepartmentName for xml path('Employee')) as EmployeesList from Employees Egroup by DepartmentName 结果：
3.如果指定零长度字符串，则将不生成包装元素。
结果：
4.可以通过在 FOR XML 中指定 root 选项来添加单个顶级元素
SQL语句：
select DepartmentName,(select ''+EmpoyeeName from Employees where DepartmentName = e.DepartmentName for xml path('Employee'),root('Root')) as EmployeesList from Employees Egroup by DepartmentName结果：
以上就是利用XML FOR PATH合并分组信息的示例代码（图文）的详细内容，更多请关注考高分网其它相关文章！
